PROBLEM 30:


A string is said to be complete if it contains all the characters from a to z.
For a user-entered string, check if it is complete or not.
Sample Input: The quick brown fox jumps over a lazy dog
Sample Output: The entered string is complete.

CODE:

 #include<stdio.h>
 main()
 {
      // Variable declaration//
     int index=0,count1[26]={0},count=0,i;
     char str[50];
     char temp;

      /*Input*/
     printf("Enter string:\n");
     gets(str);
     for(i=0;str[i];i++) //this loop will convert uppercase alphabets to lowercase
    {
    if(str[i]>=65 && str[i]<=90) //here if str array greater than 64 and less than 91 so condition will work
    {
    temp=str[i];
    str[i]=temp+32;  //here i add 32 to each array example:if array equal to 65 than add 32
    }
    }
     /* actual Working */
while (str[index] != '\0')  //this loop will run until array index not equal to null
   {
      if (str[index] >= 'a' && str[index] <= 'z')  //here I cheak that if array index >=a and <= to z
      count1[str[index]-'a']++;  //then count1 subtract by index value and increment in count1
      index++;
   }
   for (index = 0; index < 26; index++)
   {
      if (count1[index] != 0)
      count=count+1;
   }
  if(count==26)  //if count equal to 26 then this condition will run
  {
      printf("The entered string is complete");
  }
  else
  {
      printf("The entered string is not complete");
  }
    return 0;

}

Program Output:

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